Rules of Differential Calculus

We already have understood how we calculate derivatives of some simple functions. However, in most of the questions that we will face in exam, things would probably not be so simple.

Many a times we will have to calculate derivatives of complex functions, which are made by combining simple functions in various ways.

For example, we know that:

ddxsinx=cosx

ddxcosx=sinx

However, ddxsinxcosxcosx(sinx)

We will have to follow some rules of Differential Calculus to find out derivatives of such complex expressions. Let’s see some of these rules.

Rules of Differential Calculus

We will represent functions f(x) and g(x) as f and g. And their derivatives f’(x) and g’(x) as f’ and g’.

Multiplication by constant Rule

ddxcf=cf

Q. What is ddx5x2

Explanation:

ddx5x2 = 5 ddxx2 = 5 (2x) = 10x


Sum and Difference Rule

ddx[f+g]=f+g

ddx[fg]=fg

Q. What is ddx(x2+sinx)

Explanation:

ddx(x2+sinx) = ddxx2+ddxsinx = 2x + cos x


Product and Division Rule

ddx[f.g]=f.g+f.g

ddx[f/g]=f.gf.gg2

Special Case:

ddx[1/f]=ff2

Q. What is ddxxsinx

Explanation:

ddxxsinx=xddxsinx+sinxddxx = x cos x + sin x


Composition of Functions Rule

ddxfºg=(fºg).g
or $\frac{d}{dx} f(g) = f’(g) . g’

We can also represent the above in the following manner.

dydx=dydu.dudx

Q. What is ddxsinx3

Explanation:

Here, g = x3, and so f(g) = sin g

So, f’(g) = cos g = cos x3
g’ = ddxg=ddxx3=3x2

ddxsinx3=f(g).g=3x2.cosx3


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